I got around t hat problem. On Monday, April 1, 2024, Ryan Davis via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk <
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding
capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types
arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does:
* name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0)
...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect.
Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get this debugged)
could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all in
ruby-talk@ml.ruby-lang.org> wrote: the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
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