Unlike Python, the "word" operators in Ruby aren't logic operators, they're flow control. They way they work is basically a carry-over from the way that Perl handled them. They serve different purposes, and are not equivalent. On Sat, Feb 24, 2024, 03:24 Information via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
Am 19.02.24 um 11:22 schrieb botp:
On Sun, Feb 18, 2024 at 3:05 AM Information via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
Hi p(1 and 2 or 3 and 4) 1. how many brackets do we need?
none if you know the order :)
Maybe there is a misunderstanding: p(--"--) doesnt work at all (Syntax error) p((--"--) does the job. (Maybe for this the subject was misleading_
2. in my opinion the result should be 2, not 4.
What do you think?
1 and 2 or 3 and 4 => 4
evaluation left to right
1 && 2 || 3 && 4 => 2
evaluation 1st: 1 && 2 => 2 evaluation 2nd: 3 && 4 => 4 evaluation last: 2 || 4
So why should be there another result if using and/or instead of &&/|| ?
(1 and 2 or 3 and 4) != (1 && 2 || 3 && 4)
- That shouldn't be the case!
Andreas ______________________________________________ ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info -- https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...