Am 19.02.24 um 11:22 schrieb botp:

On Sun, Feb 18, 2024 at 3:05 AM Information via ruby-talk <ruby-talk@ml.ruby-lang.org> wrote:

Hi
p(1 and 2 or 3 and 4)
1. how many brackets do we need?

none if you know the order :)

Maybe
      there is a misunderstanding:

p(--"--)
      doesnt work at all (Syntax error)

p((--"--)
      does the job. (Maybe for this the subject was misleading_

2. in my opinion the result should be 2, not 4.
What do you think?

> 1 and 2 or 3 and 4
=> 4

evaluation left to right

> 1 && 2 || 3 && 4
=> 2

evaluation 1st: 1 && 2 => 2

evaluation 2nd: 3 && 4 => 4

evaluation last: 2 || 4

So why should be there another result if using and/or instead of &&/|| ?

(1 and 2 or 3 and 4) != (1 && 2 || 3 && 4)

- That shouldn't be the case!

Andreas