[ruby-talk:444441] encode on nonencoded capable object.
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding capable object ( [1;4mArgumentError [m [1m) [m Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types arrays with the additional values and not the previous values are set. What does the error mean and how to fix it? `ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]] ptl.shuffle() str=ptl[0]+ptl[1]+ptl[2] cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1 end types=Array.new(19) { [[],[],[]] } pwt=w[0]+w[1]+w[2] types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end for i in 0..(str.length()-1) types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle() for j in 0..5 sampstr.push typeslist[j] end for j in 6..12 sampwk. push typeslist[j] end types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk <ruby-talk@ml.ruby-lang.org> wrote:
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does: * name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0) ...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect. Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get this debugged) could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all in the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
I got around t hat problem. On Monday, April 1, 2024, Ryan Davis via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk <
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding
capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types
arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does:
* name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0)
...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect.
Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get this debugged)
could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all in
ruby-talk@ml.ruby-lang.org> wrote: the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info --
https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...
https://codeshare.io/P84e1Q I don't know if it will be more clear but Pokemon have types and so do their moves. A move doesn't have to be the same type as the pokemon. A pokemon of a type can resist a move of a type or be weak to it or immune or just normally effective. As far code goes, it is still not working right- type and typesgen are not combining correctly On Mon, Apr 1, 2024 at 5:14 AM Ryan Davis via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does:
* name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0)
...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect.
Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get this debugged)
could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all in the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info -- https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...
Mark, what does the left and right side of the first array's subelements represent? tep=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]] As Ryan noted it appears to be an index of 17 things where the right side may be nothing? I also note that the right hand values also fit into 0-16 as a range. I find myself intrigued in the same way I can be with word puzzles. So far I think: 1. single pairs [2] correspond to no other entry in the list 2. [0, 3] would be 0 entry relates to entry 3 In plain english what does this array mean? Once I see `str=tep[0]+tep[1]+tep[2]` this throws me off the rails since not all teps are [n, n] but some are [n]. -Tom -Tom -Tom On Mon, Apr 1, 2024 at 8:29 AM Mark Smith via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
https://codeshare.io/P84e1Q I don't know if it will be more clear but Pokemon have types and so do their moves. A move doesn't have to be the same type as the pokemon. A pokemon of a type can resist a move of a type or be weak to it or immune or just normally effective. As far code goes, it is still not working right- type and typesgen are not combining correctly
On Mon, Apr 1, 2024 at 5:14 AM Ryan Davis via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does:
* name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0)
...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect.
Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get this debugged)
could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all in the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info -- https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...
______________________________________________ ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info -- https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...
-- blog: http://blog.enebo.com twitter: tom_enebo mail: tom.enebo@gmail.com
They are pokemon types. Pokemon can have up to two types. For you the numbers are pure abstractions. On Tuesday, April 2, 2024, Thomas E Enebo via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
Mark, what does the left and right side of the first array's subelements represent?
As Ryan noted it appears to be an index of 17 things where the right side may be nothing? I also note that the right hand values also fit into 0-16 as a range. I find myself intrigued in the same way I can be with word
1. single pairs [2] correspond to no other entry in the list 2. [0, 3] would be 0 entry relates to entry 3 In plain english what does this array mean? Once I see `str=tep[0]+tep[1]+tep[2]` this throws me off the rails since not all teps are [n, n] but some are [n]. -Tom
-Tom
-Tom
On Mon, Apr 1, 2024 at 8:29 AM Mark Smith via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
https://codeshare.io/P84e1Q I don't know if it will be more clear but Pokemon have types and so do
As far code goes, it is still not working right- type and typesgen are not combining correctly On Mon, Apr 1, 2024 at 5:14 AM Ryan Davis via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk <
ruby-talk@ml.ruby-lang.org> wrote:
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding
capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the
types arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does:
* name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0)
...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect.
Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get
tep=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]] puzzles. So far I think: their moves. A move doesn't have to be the same type as the pokemon. A pokemon of a type can resist a move of a type or be weak to it or immune or just normally effective. this debugged)
could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all
in the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info --
https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...
______________________________________________ ruby-talk mailing list -- ruby-talk@ml.ruby-lang.org To unsubscribe send an email to ruby-talk-leave@ml.ruby-lang.org ruby-talk info -- https://ml.ruby-lang.org/mailman3/postorius/lists/ruby-talk.ml.ruby-lang.org...
-- blog: http://blog.enebo.com twitter: tom_enebo mail: tom.enebo@gmail.com
https://codeshare.io/ONk3lv This works. It is not elegant. str etc are the lists of the types combined from 3 pokemon. On Tue, Apr 2, 2024 at 12:09 AM Thomas E Enebo via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
Mark, what does the left and right side of the first array's subelements represent?
tep=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
As Ryan noted it appears to be an index of 17 things where the right side may be nothing? I also note that the right hand values also fit into 0-16 as a range. I find myself intrigued in the same way I can be with word puzzles. So far I think:
1. single pairs [2] correspond to no other entry in the list 2. [0, 3] would be 0 entry relates to entry 3
In plain english what does this array mean? Once I see `str=tep[0]+tep[1]+tep[2]` this throws me off the rails since not all teps are [n, n] but some are [n].
-Tom
-Tom
-Tom
On Mon, Apr 1, 2024 at 8:29 AM Mark Smith via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
https://codeshare.io/P84e1Q I don't know if it will be more clear but Pokemon have types and so do their moves. A move doesn't have to be the same type as the pokemon. A pokemon of a type can resist a move of a type or be weak to it or immune or just normally effective. As far code goes, it is still not working right- type and typesgen are not combining correctly
On Mon, Apr 1, 2024 at 5:14 AM Ryan Davis via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
On Mar 30, 2024, at 16:14, Mark Smith via ruby-talk < ruby-talk@ml.ruby-lang.org> wrote:
That seems to be the main error but the full error message is [1mTraceback [m (most recent call last): 4: from playground.rb:42:in `<main>' 3: from playground.rb:42:in `p' 2: from playground.rb:42:in `inspect' 1: from playground.rb:42:in `inspect' playground.rb:42:in `inspect': [1mcannot set encoding on non-encoding capable object ( [1;4mArgumentError [m [1m) [m
Thanks for your help in advance. Maybe it is because I need to combine the previous values of the types arrays with the additional values and not the previous values are set. What does the error mean and how to fix it?
There's a lot going on with this code that I'm not gonna touch on... I'm not going to help with the error because I'm unwilling to run such obfuscated code right now. But I will say that code readability matters and helps to convey what the code does:
* name things so they convey what they're doing * name your magic numbers * indent the code correctly * add blank lines to separate different ideas into their own paragraphs * say what you mean (eg .empty? vs .length==0)
...all of these things help you and anyone who winds up reading the code.
`ptl=[[0,3],[1,5],[2],[3,14],[4,0],[5,0],[6,15],[7,9],[8,7],[9,11],[10,16],[11,6],[12],[13,9],[14],[15,14],[16]]
Some of these aren't pairs. Are you sure that you can mix nil and integers? I don't see checks to that effect.
Also, the first item is literally just the slot count. Not terribly valuable and could be had with `with_index`
ptl.shuffle()
ptl.shuffle returns a new array. So this doesn't do what you want.
str=ptl[0]+ptl[1]+ptl[2]
this never differs as a result (probably a good thing until you get this debugged)
could be `str = ptl.first 3`
cr=3 i=0 w=Array.new(2) { [] } until i==3 p ptl[cr] w[i]=ptl[cr] if ((w[i]&str).length()==0) i+=1 end cr+=1
end types=Array.new(19) { [[],[],[]] }
pwt=w[0]+w[1]+w[2]
types[17]=[[pwt],[str]] for i in 0..(pwt.length()-1) types[pwt[i]]=[[],[19]] end
what is the point of this code if you're literally overwriting it all in the next block?
for i in 0..(str.length()-1)
`str.length.times do |i|`
types[str[i]]=[[19],[]] end typeslist=Array.new(17) {|i| i } sampstr=Array.new(6) { [] } sampwk=Array.new(6) { [] } for i in 0..types.length()-1 typeslist.shuffle()
ditto
for j in 0..5 sampstr.push typeslist[j] end
sampstr.append typeslist.take 6 or sampwk.append typeslist[0..5]
for j in 6..12 sampwk. push typeslist[j] end
sampwk.append typeslist.drop(6).take(6) or sampwk.append typeslist[6..12]
types[0][i]=sampstr.push types[0][i] types[1][i]=sampwk.push types[1][i] types[2][i]=typeslist[13] end p types`
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participants (3)
-
Mark Smith -
Ryan Davis -
Thomas E Enebo