Issue #20738 has been updated by matz (Yukihiro Matsumoto). I don't want to add a special value (Hash::DROP) nor special syntax (?key:) here. Use `h = {foo: 1}; h[:bar] = 2 if bar?`. Matz. ---------------------------------------- Feature #20738: Removing a specific entry from a hash literal https://bugs.ruby-lang.org/issues/20738#change-110036 * Author: ursm (Keita Urashima) * Status: Open ---------------------------------------- Sometimes I want to decide whether or not to add a particular entry to a hash depending on a condition. If the entire hash does not use nil, I can use Hash#compact. ```ruby { foo: 1, bar: bar? ? 2 : nil }.compact ``` But if I want to remove only a specific entry while leaving the other nil, it is somewhat cumbersome. I have to either assign the hash once and change it destructively, or use Hash#reject. ``` ruby h = { foo: 1, baz: nil } h[:bar] = 2 if bar? ``` ``` ruby { foo: 1, bar: bar? ? 2 : :drop, baz: nil }.reject {|_, v| v == :drop } ``` As a suggestion, how about a special value that indicates an invalid key for the hash? With this, the above example could be written like this: ``` ruby { foo: 1, bar: bar? ? 2 : Hash::DROP, baz: nil } #=> {foo: 1, baz: nil} ``` -- https://bugs.ruby-lang.org/