Issue #19864 has been updated by jgomo3 (Jesús Gómez). File range_test_2.rb added File range_test_3.rb added I tested the idea with whole numbers, and it doesn't fail. I tested the idea with dates not in the extremes, and it DOES fail. Attached 2 examples. The first one using numbers: ``` (..0) === 0 ``` Which works fine both in Ruby 3.1 and 3.2 The second one using different dates. In particular, checking if "yesterday" is in the range of "..today": ``` require 'date' today = Date.today yesterday = today - 1 (..today) === yesterday ``` And it fails in 3.2, but works fine in 3.1. ---------------------------------------- Bug #19864: Ruby 3.2 Changed Behavior With One Sided Ranges https://bugs.ruby-lang.org/issues/19864#change-104482 * Author: Aesthetikx (John DeSilva) * Status: Open * Priority: Normal * ruby -v: 3.3.0 * Backport: 3.0: UNKNOWN, 3.1: UNKNOWN, 3.2: UNKNOWN ---------------------------------------- Thank you for taking the time to read my issue. I know there has been some previous discussion here https://bugs.ruby-lang.org/issues/19533 regarding a similar issue, although I think this is different. I apologize if this has already been addressed. Prior to Ruby 3.2, you could use a beginless or endless range, and use === (or a case statement) to determine if a given date matched that range. For example, (..today) === yesterday would have returned true, and (tomorrow..) === today would have returned false. Please see my attached file for a more concrete example. Starting with Ruby 3.2, this results in "`===': cannot determine inclusion in beginless/endless ranges (TypeError)". I can imagine that there is difficulty and ambiguity with these infinite ranges and non numeric objects, however I do feel that these examples with dates should work, especially since (..Date.today).cover?(Date.today) still works as expected. ---Files-------------------------------- range_test.rb (928 Bytes) range_test_2.rb (411 Bytes) range_test_3.rb (162 Bytes) -- https://bugs.ruby-lang.org/