Issue #20931 has been updated by stephenprater (Stephen Prater). That works for me - thanks for the explanation. ---------------------------------------- Bug #20931: Using `in` as an expression requires extra parentheses https://bugs.ruby-lang.org/issues/20931#change-110856 * Author: stephenprater (Stephen Prater) * Status: Rejected * ruby -v: 3.3.1 * Backport: 3.1: UNKNOWN, 3.2: UNKNOWN, 3.3: UNKNOWN ---------------------------------------- TBH - I'm not sure if this is a bug or not - but it certainly surprising behavior and I'd at least like to understand it. Given a hash t - that can be pattern matched: `t = {a: 1, b:1 }` ``` ruby r = t in {a: 1, c:1 } # returns `false` r # {a: 1, c: 1} wat ``` Presumably this is because `=` binds higher than `in` - so that expression is equivalent to `(r = t) in {a: 1, c: 1}` But in that case - why does using the results of `in` require an additional set of parentheses to avoid a syntax error when the result of the expression is used as an argument to a method? ``` ruby puts(t in {a: 1, c: 1}) # syntax error puts((t in {a: 1, c: 1}) # false ``` Especially since this works fine: ``` ruby puts(case t; in { a: 1, c:1 }; true; else false; end) ``` -- https://bugs.ruby-lang.org/