Issue #20770 has been updated by AlexandreMagro (Alexandre Magro). nobu (Nobuyoshi Nakada) wrote in #note-1:
In the previous trial syntax, the receiver of RHS was the result of LHS.
In your proposal, the receiver of RHS is the same as LHS, and the LHS result is passed as an implicit argument?
Exactly, this is the expected behavior of the pipe operator in other functional languages, such as Elixir. In those languages, the left-hand side (LHS) value is passed directly as an argument to the function on the right-hand side (RHS), either as the first or last argument depending on the language. For example, in Elixir, you might write: ```elixir value = value |> add(3) |> square() |> half() ``` My proposal for Ruby offers a more flexible approach. The LHS value can be passed as an explicit argument (using `_1` or `it`), allowing for greater control over how the RHS function handles the received value. Additionally, this approach simplifies the implementation by treating RHS as executable block, just as we already do with `.then`. ---------------------------------------- Feature #20770: A *new* pipe operator proposal https://bugs.ruby-lang.org/issues/20770#change-109951 * Author: AlexandreMagro (Alexandre Magro) * Status: Open ---------------------------------------- Hello, This is my first contribution here. I have seen previous discussions around introducing a pipe operator, but it seems the community didn't reach a consensus. I would like to revisit this idea with a simpler approach, more of a syntactic sugar that aligns with how other languages implement the pipe operator, but without making significant changes to Ruby's syntax. Currently, we often write code like this: ```ruby value = half(square(add(value, 3))) ``` We can achieve the same result using the `then` method: ```ruby value = value.then { add(_1, 3) }.then { square(_1) }.then { half(_1) } ``` While `then` helps with readability, we can simplify it further using the proposed pipe operator: ```ruby value = add(value, 3) |> square(_1) |> half(_1) ``` Moreover, with the upcoming `it` feature in Ruby 3.4 (#18980), the code could look even cleaner: ```ruby value = add(value, 3) |> square(it) |> half(it) ``` This proposal uses the anonymous block argument `(_1)`, and with `it`, it simplifies the code without introducing complex syntax changes. It would allow us to achieve the same results as in other languages that support pipe operators, but in a way that feels natural to Ruby, using existing constructs like `then` underneath. I believe this operator would enhance code readability and maintainability, especially in cases where multiple operations are chained together. Thank you for considering this proposal! -- https://bugs.ruby-lang.org/