Am 19.02.24 um 11:22 schrieb botp:
On Sun, Feb 18, 2024 at 3:05 AM Information via ruby-talk <ruby-talk@ml.ruby-lang.org <mailto:ruby-talk@ml.ruby-lang.org>> wrote:
Hi p(1 and 2 or 3 and 4) 1. how many brackets do we need?
none if you know the order :)
Maybe there is a misunderstanding: p(--"--) doesnt work at all (Syntax error) p((--"--) does the job. (Maybe for this the subject was misleading_
2. in my opinion the result should be 2, not 4. What do you think?
1 and 2 or 3 and 4 => 4
evaluation left to right
1 && 2 || 3 && 4 => 2
evaluation 1st: 1 && 2 => 2 evaluation 2nd: 3 && 4 => 4 evaluation last: 2 || 4
So why should be there another result if using and/or instead of &&/|| ? (1 and 2 or 3 and 4) != (1 && 2 || 3 && 4) - That shouldn't be the case! Andreas