Issue #19075 has been updated by sawa (Tsuyoshi Sawada).
When we want to reverse the direction in any sense, such as the direction of search, in my
understanding, it's Ruby's custom to use the word "reverse" or a prefix
"r":
`Enumerable#revserse_each`
`Array#rindex`
`String#rindex`
`String#rjust`
`String#rpartition`
`String#rstrip`
To be consistent, I think it is better to have independent methods as in the original
proposal, but with method names like:
`reverse_bsearch`
`bsearch_rindex`
----------------------------------------
Feature #19075: Binary searching for the last element
https://bugs.ruby-lang.org/issues/19075#change-104447
* Author: kyanagi (Kouhei Yanagita)
* Status: Open
* Priority: Normal
----------------------------------------
My latest proposal is
https://bugs.ruby-lang.org/issues/19075#note-6.
I will leave the initial proposal below.
---
PR:
https://github.com/ruby/ruby/pull/6611
(I'm going to talk about `Array` here, but the same argument can be made for `Range`.
If `Array#bsearch_last` is acceptable, I will work also for `Range`.)
Ruby's bsearch returns the first element which satisfies the given block.
```ruby
# Search the first element greater than 18
array = [10, 15, 20, 25]
array.bsearch { |x| x > 18 } # => 20
```
If we want the last element, we need to invert the condition and step backward.
```ruby
# Search the last element less than 18
array = [10, 15, 20, 25]
index = array.bsearch_index { |x| !(x < 18) }
array[index-1] # => 15
```
Of course, we need to consider `nil` and the boundary.
```ruby
# Search the last element less than 100
index = array.bsearch_index { |x| !(x < 100) } # => nil
if index.nil?
array.last # => 25
else
array[index-1]
end
```
```ruby
# Search the last element less than 0
index = array.bsearch_index { |x| !(x < 0) } # => 0
if index.nil?
array.last
elsif index == 0
nil
else
array[index-1]
end
```
This is where mistakes can easily be made, so I propose `Array#bsearch_last` and
`Array#bsearch_last_index`.
`Array#bsearch_last` returns the last element which satisfies the given block.
`Array#bsearch` requires that all false-evaluating elements precede all true-evaluating
elements. As is clear from the meaning of the method, conversely to `bsearch`,
`bsearch_last` requires that all true-evaluating elements precede all false-evaluating
elements. (If `bsearch_last` is acceptable, the name "find-minimum mode" should
be changed.)
```ruby
array = [10, 15, 20, 25]
array.bsearch_last { |x| x < 18 } # => 15
array.bsearch_last { |x| x < 100 } # => 25
array.bsearch_last { |x| x < 0 } # => nil
```
There are several possible options for find-any mode.
(1) `bsearch_last` does not support find-any mode.
A block for `bsearch_last` must return `true`, `false` or `nil`.
```
[1, 2, 3].bsearch_last { 0 } # => TypeError
```
My pull request tentatively includes this implementation.
(2) `bsearch_last` supports find-any mode and it behaves like `bsearch`.
`bsearch` with find-any mode returns an element, for which the block returns zero.
If multiple elements satisfy the condition, it is not determined which of them will be
returned.
It is conceivable that `bsearch_last` behaves in the same way as `bsearch`.
```
# current behavior
# It is not specified whether `:b`, `:c`, or `:d` is returned.
[[1,:a], [2, :b], [2, :c], [2, :d], [3, :e]].bsearch { |a, b| 2 <=> a } # => [2,
:c]
```
(3) `bsearch_last` supports find-any mode and returns the last element. Make `bsearch`
return the first element.
Change the behavior of `bsearch` to return the first element for which the block returns
zero.
`bsearch_last` returns the last element for which the block returns zero.
```
# Change it like this:
[[1,:a], [2, :b], [2, :c], [2, :d], [3, :e]].bsearch { |a, b| 2 <=> a } # => [2,
:b]
[[1,:a], [2, :b], [2, :c], [2, :d], [3, :e]].bsearch_last { |a, b| 2 <=> a } # =>
[2, :d]
```
(If this option is adopted, the name "find-any mode" should be renamed.)
--
https://bugs.ruby-lang.org/