Issue #19231 has been updated by Eregon (Benoit Daloze).
IMHO Integer makes sense so one can step by N from 0 to infinity with
`0.step(Float::INFINITY, 10)` (with `Numeric#step`), since there is no
`Integer::INFINITY`.
Using Float also can cause significant errors with a big enough step or values.
So the rule would be "use floats if `receiver` or `step` is Float (ignore
`to/limit`'s type), otherwise leave them as-is.
The keyword form already uses integers for "step infinitely":
```ruby
0.step(by: 10).take 2
=> [0, 10]
0.step(by: 10) { break _1 }
=> 0
```
Probably we need to be consistent with `Range#step` too:
```ruby
(0..).step(10) { break _1 }
=> 0
(0..).step(10).take 2
=> [0, 10]
(0..Float::INFINITY).step(10) { break _1 }
=>
0.0
(0..Float::INFINITY).step(10).take 2
=> [0.0,
10.0]
```
----------------------------------------
Bug #19231: Integer#step and Float::INFINITY - inconsistent behaviour when called with and
without a block
https://bugs.ruby-lang.org/issues/19231#change-100625
* Author: andrykonchin (Andrew Konchin)
* Status: Open
* Priority: Normal
* ruby -v: 3.1.2
* Backport: 2.7: UNKNOWN, 3.0: UNKNOWN, 3.1: UNKNOWN
----------------------------------------
The initial issue was reported here
https://github.com/oracle/truffleruby/issues/2797.
`0.step(Float::INFINITY, 10)` returns:
- `Integers` when called with a block
- `Floats` when called without a block
I would expect `Floats` to be returned in both cases.
Examples:
```ruby
0.step(Float::INFINITY, 10).take(1).map(&:class)
=> [Float]
```
```ruby
0.step(Float::INFINITY, 10) { |offset| p offset.class; break }
# Integer
```
When `to` argument is a finite `Float` value then calling with a block returns `Floats` as
well:
```ruby
0.step(100.0, 10) { |offset| p offset.class; break }
# Float
```
Wondering whether it's intentional behaviour.
I've found a related issue
https://bugs.ruby-lang.org/issues/15518.
--
https://bugs.ruby-lang.org/